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Re : average survey report

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Hi,

You could use the query below to generate the report.

SELECT  MAX(ti.FIRST_NAME) "Technician",
(sum(sadt.RATING)/(count(sadt.RATING)*(select count(SURANSID) from surveyanswers)))*100 "% Rating" FROM SurveyPerRequest spr
INNER JOIN SurveyPerRequestExt spre ON spr.SURVEYID=spre.SURVEYID
LEFT JOIN SurveyDetails sdt ON spre.SURVEYID=sdt.SURVEYID
LEFT JOIN SurveyAnswers sadt ON sdt.SURANSID=sadt.SURANSID
LEFT JOIN WorkOrder wo ON spr.WORKORDERID=wo.WORKORDERID
LEFT JOIN WorkOrderStates wos ON wo.WORKORDERID=wos.WORKORDERID
LEFT JOIN SDUser td ON wos.OWNERID=td.USERID
LEFT JOIN AaaUser ti ON td.USERID=ti.USER_ID 
 group by td.USERID

Regards,
Stephen

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